By J N Fawcett; J S Burdess
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Extra resources for Basic mechanics with engineering applications
These values agree with values obtained from the analytical method. The angular accelerations of the links may be found in a similar manner. Again starting with point A as a point on link OIA, we know that its acceleration is radially inwards along AO l • There is no tangential component of is constant. For link AB, which is in general plane motion, aA since w (viii) Consider the right-hand side of this equation. The vector aA is known in both magnitude and direction. The acceleration aBA of B relative to A has two components, (aBA).
The accelerations of the system can be found in a similar manner. Crank OR rotates about a fixed point so that aR = (aR)r + (aR)t, where (aR)r = (Jh along RO and (aR)t = ivr perpendicular to RO. In this case W = 0 (constant angular velocity) so that (aR)t = o. The acceleration of R is therefore radially inwards along RO and has magnitude aR = w 2r. The link RS is in general plane motion, and we now know the acceleration . of end R of this link. 31) we have In this vector equation we know the magnitude and direction of a R • The line of as must lie along OX, and aSR has two components, (aSR)r = 4>2[ along SR, and (aSR)t = ~I perpendicular to RS.
44 Kinematics Graphical method By drawing Fig. 57(b) to scale, for a given value of fJ, Xs can be found. Next the velocity of S can be determined by considering each body in the mechanism in tum, starting with the input link. Link OR is rotating about a fixed point O. The velocity of point R therefore has magnitude (i) and has direction perpendicular to OR (see p. 25) as shown in Fig. 58. Link RS is in general plane motion. 30) gives (ii) In this equation we know VR in both magnitude and direction.
Basic mechanics with engineering applications by J N Fawcett; J S Burdess